A gaseous alkane is exposed to oxygen. The volume of O2 for complete combustion and the CO2 formed are in the ratio 7:4. The molecular mass (in g) of the alkane is :
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Solution
Given that the gas is alkane and thus, its formula is CnH2n+2. For combustion, CnH2n+2[n+(n+1)/2]O2→nCO2+(n+1)H2O ∴VolumeofO2usedVolumeofCO2formed=74 ∴[n+(n+1)/2]n=74 Therefore, n=2. AlkaneisC2H6. The molar mass of alkane is 30 g/mol.