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Standard X
Chemistry
Classification of Hydrocarbons
A gaseous hyd...
Question
A gaseous hydrocarbon (12mL) is exploded with excess of oxygen.On cooling the contraction in volume is 48mL and their is further contraction of 48mL in volume when passed through lime water. The molecular formula of hydrocarbon is
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Q.
A gaseous hydrocarbon (
12
ml) is exploded with an excess of oxygen. On cooling, the contraction in volume is
48
ml and there is further contraction of
48
ml in volume when passed through
C
O
2
. The molecular formula of hydrocarbon is:
Q.
Ten millilitres of a gaseous hydrocarbon was exploded with oxygen. After the explosion, there was a contraction of 20 ml in volume. On shaking the residual gaseous mixture with KOH, there was a further concentration of 20 ml in volume. Molecular formula is
C
x
H
y
. All the volumes were recorded at the same temperature and pressure. Here
x+y
is:
Q.
Ten millilitres of a gaseous hydrocarbon was exploded with oxygen. After the explosion, there was a contraction of
20
m
l
in volume. On shaking the residual gaseous mixture with
K
O
H
, there was a further concentration of
20
m
l
in volume. Calculate the molecular formula. All the volumes were recorded at same temperature and pressure.
Q.
7.5
m
L
of a hydrocarbon gas was exploded with an excess of oxygen. On cooling, it was found to have undergone a contraction of 1
5
m
L
. If the vapour density of the hydrocarbon is
14
, determine its molecular formula.(C=12, H=1)
Q.
Assertion :When gaseous hydrocarbon are completely burnt in eudiometer tube with excess of
O
2
and after cooling there is a contraction in the volume of gases. Reason: The volume of
H
2
O
is not considered.
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