wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A gaseous hydrocarbon contains 82.76 % of carbon. Given that its vapour density is 29, find its molecular formula

Open in App
Solution

Element % mass atomic mass no of atoms simplest ratio rounding of ratio
C 82.76 12 82.7612=6.89 6.896.89=1 1×2=2
H 17.24 1 17.241=17.24 17.246.89=2.5 2.5×2=5


Empirical formula is C2H5
Molecular weight = 2 × Vapour density
Molecular weight = n × (Empirical formula weight)
58 = n × (12 × 2 + 1 × 5)
n = 2
So, molecular formula = C4H10


flag
Suggest Corrections
thumbs-up
84
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Empirical and Molecular Formula
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon