A gaseous hydrocarbon 'X' on reaction with bromine in light forms a mixture of two monobromo alkanes and HBr. The hydrocarbon' X' can have a molecular formula:

C_{2} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{3} H_{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{3} H_{8}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{4} H_{10}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $C_{4} H_{10}$
C $C_{3} H_{8}$
On the bromination of propane and isobutane, two products are obtained on their photobromination.
Molecular formula of propane is $C_{3} H_{8}$ and that of isobutane is $C_{4} H_{10}$

So, the alkane can have molecular formulas: $C_{3} H_{8} o r C_{4} H_{10}$
Hence, Options "C" & "D" are correct answers.

Suggest Corrections

Similar questions

C_{2} H_{6}, C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2}

{CH}_{4}

C_{2} H_{6}, C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2} and C H_{4} .

C_{2} H_{6}

C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2}

C H_{4}

C_{2} H_{6}, C_{3} H_{8}, C_{3} H_{6}, C_{2} H_{2}

{CH}_{4}

Join BYJU'S Learning Program