A gaseous mixture consists of 16 g He and 16 g O 2 - The ratio of specific heats C p - C V of the mixture isA- 1-54B- 1-59C- 1-62D- 1-4

The correct option is C 1.62For He, nbsp; nbsp;C_v1=3R2 No. of moles n_1=16M_He=164=4 For O_2, nbsp; nbsp;C_v2=5R2 No. of moles n_2=16M_O_2=1632=1 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Heat Capacity

A gaseous mix...

Question

A gaseous mixture consists of $16 g H e$ and $16 g O_{2}$ . The ratio of specific heats $\frac{C_{p}}{C_{v}}$ of the mixture is

1.59

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.62

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.54

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $1.62$
For $H e$ ,
$C_{v 1} = \frac{3 R}{2} No. of moles n_{1} = \frac{16}{M_{H e}} = \frac{16}{4} = 4$

For $O_{2}$ ,
$C_{v 2} = \frac{5 R}{2} No. of moles n_{2} = \frac{16}{M_{O_{2}}} = \frac{16}{32} = \frac{1}{2}$

We know,
$C_{v (m i x)} = \frac{n_{1} C_{v 1} + n_{2} C_{v 2}}{n_{1} + n_{2}} = \frac{4 (\frac{3}{2} R) + \frac{1}{2} (\frac{5}{2} R)}{4 + \frac{1}{2}} = \frac{29 R}{18}$

$C_{p} = C_{v} + R = \frac{47 R}{18} γ = \frac{C_{p}}{C_{v}} = \frac{47}{29} = 1.62$

Suggest Corrections

Similar questions

Q. A gaseous mixture consists of

16 g H e

and

16 g O_{2}

. The ratio of specific heats

\frac{C_{p}}{C_{v}}

of the mixture is

Q. A gaseous mixture consists of

16 g

of helium and

16 g

of oxygen. The ratio

\frac{C_{P}}{C_{V}}

of the mixture is

Q. The gaseous mixture consists of

16

of helium and

16

of oxygen. The ratio

\frac{C_{p}}{C_{v}}

of the mixture is :-

Q. Calculate the specific heat capacity

C_{v}

of a gaseous mixture consisting of

v_{1}

moles of a gas of adiabatic exponent

γ_{1}

and

v_{2}

moles of another gas of adiabatic exponent

γ_{2}

Q. Equal volumes of two monoatomic gases,

A

and

B

, at same temperature and pressure are mixed. The ratio of specific heats

(C_{p} / C_{v})

of the mixture will be:

Join BYJU'S Learning Program

A gaseous mixture consists of 16 g He and 16 g O2. The ratio of specific heats CpCv of the mixture is

The correct option is B 1.62For He, Cv1=3R2No. of moles n1=16MHe=164=4 For O2, Cv2=5R2No. of moles n2=16MO2=1632=12 We know, Cv(mix)=n1Cv1+n2Cv2n1+n2 =4(32R)+12(52R)4+12 =29R18 Cp=Cv+R=47R18γ=CpCv=4729=1.62

A gaseous mixture consists of $16 g H e$ and $16 g O_{2}$ . The ratio of specific heats $\frac{C_{p}}{C_{v}}$ of the mixture is