CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equipartition Theorem

A gaseous mix...

Question

A gaseous mixture containing equal moles of $H_{2}, O_{2}$ and $H e$ is subjected to series of effusion steps. The composition (by moles) of effused mixture after 4 effusion steps is $x : 1 : y$ respectively. Then the value of $(\frac{x}{y})$ is:

Open in App

Solution

As rate of effusion is inversely proportional to square root of molar mass, so ratio of hydrogen to helium (when for oxygen it is one) is 4:1.

Suggest Corrections

thumbs-up

0

Similar questions

Q. A gaseous mixture of

H e

C H_{4}

gases with mole ratio 2 : 1 respectively is placed in a container and allowed to effuse through a small orifice.

X m l

H e

gas effuses in 5 seconds. The time required to effuse same volume of

C H_{4}

Q. The number of effusion steps required to convert a mixture of

H_{2}

O_{2}

from 240 : 1600 (by mass) to 3072 : 20 (by mass) is:

Q. The number of effusion steps required to convert a mixture of

H_{2}

O_{2}

from 240:1600(by mass) to 3072:20(by mass) is :

Q. The mole fraction of

H e

0.4

in gaseous mixture

H e

C H_{4}

. If both the gaseous are effusing through the constant area of the orifice of the container, then what will be

%

composition by volume of

C H_{4}

gas effusing out initially ?

Q. A mixture of

C H_{4}

O_{2}

is used as an optimal fuel if

O_{2}

is present in thrice the amount required theoretically for combustion of

C H_{4}

. Calculate number of effusions steps required to convert a mixture containing

1

C H_{4}

in 193 parts mixture (parts by volume). If calorific value (heat evolved when 1 mole is burnt) of

C H_{4}

is 100 cal/mole & if after each effusion 80% of

C H_{4}

is collected. Find out what initial mole of each gas in initial mixture required for producing 1000 cal of energy after processing.
[Given

(0.9)^{5} = 0.6

]

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Theory of Equipartitions of Energy

PHYSICS

Watch in App

explore_more_icon

Explore more

Equipartition Theorem

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon