Question

A gaseous mixture containing $He,C{H}_4$ and $S{O}_2$ was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially?

( Given : mixture contains $He,C{H}_4$ and $S{O}_2$ in 1:2:3 mole ratio ).

• A. $\sqrt{2}:\sqrt{2}:3$
• B. $2:2:3$
• C. $4:4:3$
• D. $1:1:3$

Answer 1

Answer: (C)

$4:4:3$

A gaseous mixture containing $He,C{H}_4$ and $S{O}_2$ was allowed to effuse through a fine hole then, the ratio of effusing gases:

$\frac{n_{He}}{n_{C{H}_4}}=\frac{1}{2}\sqrt{\frac{16}{4}}=\frac{1}{2}\times \frac{4}{2}=\frac{4}{4}=1$

$\frac{n_{He}}{n_{S{O}_2}}=\frac{1}{3}\sqrt{\frac{64}{4}}=\frac{1}{3}\times \frac{8}{2}=\frac{4}{3}$

Hence, the molar ratio of the gases coming out will be $He:C{H}_4:S{O}_2$ is $4:4:3$