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Elevation in Boiling Point

A gaseous mix...

Question

A gaseous mixture contains 4.0 g of $H_{2}$ and 56.0 g of $N_{2}$ . The mole fraction of $H_{2}$ in the mixture is:

A

0.1

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B

0.2

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C

0.5

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D

0.8

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Solution

The correct option is B 0.5
$X_{H_{2}} = \frac{n_{H_{2}}}{n_{H_{2}} + n_{N_{2}}}$ $= \frac{\frac{4}{2}}{\frac{4}{2} + \frac{56}{28}}$ $= \frac{2}{2 + 2} = \frac{1}{2}$ $= 0.5$

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