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Concentration Terms - An Introduction (w/w etc)

A gaseous mix...

Question

A gaseous mixture contains 50% helium and 50% methane by volume. What is the percentage by mass of methane in the mixture?

A

19.97%

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B

20.05%

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C

50%

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D

80%

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Solution

The correct option is D 80%
Molar and volume ratio will be same, i.e., 1:1.
$∴$ Mass of 1 mole $C H_{4}$ and $H e$ will be 16 and 4 g respectively.
Percentage by mass of $C H_{4}$ = $\frac{Mass of C H_{4}}{Total mass} \times 100$
$= \frac{16}{20} \times 100 = 80 %$

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Concentration Terms - An Introduction (w/w etc)

Standard XII Chemistry

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