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Percentage Composition

A gaseous mix...

Question

A gaseous mixture contains $C H_{4}$ and $C_{2} H_{6}$ in equimolecular proportion. The weight of 2.27 litres of this mixture at STP is:

3 g

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4.6 g

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1.6 g

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2.3 g

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Solution

The correct option is B 2.3 g
Mol wt of $C H_{4} = 16 g / m o l$

Mol wt of $C_{2} H_{6} = 30 g / m o l$

Total $= 46 g / m o l$

$\Rightarrow 1$ Mol wt of $C H_{4} = 22.4 L$

$1$ Mol wt of $C_{2} H_{6} = 22.4 L$

$\Rightarrow 46 g / m o l$ of $C H_{4} + C_{2} H_{6} = 22.4 + 22.4$

$= 44.8 L$

$\Rightarrow 46 g / m o l = 44.8 L$

$\Rightarrow x = 2.27 L$

$\Rightarrow x = \frac{46 \times 2.27}{44.8} = 2.33 g$

Hence, the answer is $2.33 g .$

Hence, the correct option is $D$

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