A gaseous mixture of $C O_{2}$ and $S O_{2}$ was to be identified in a laboratory. Mr. $X$ and Mr. $Y$ performed the experiments as shown in the figure above with common reagents but at different stages.

$Mr. Y: Both C O_{2} a n d S O_{2} react with C a (O H)_{2} and lime water turns milky. No effect on K_{2} C r_{2} O_{7}$ .

$Mr. X : S O_{2} t u r n s K_{2} C r_{2} O_{7} green and C O_{2} does not react at this stage.$
$C O_{2} reacts at stage II with C a (O H)_{2} and it turns milky .$

True

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False

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Solution

The correct option is A True
Carbon dioxide passed into limewater gives a milky solution. This is due to the insoluble suspension of $C a C O_{3}$ $_{formed.}$

We know that both $C O_{2}$ and $S O_{2}$ can turn lime water milky whereas, $S O_{2}$ acts as a reducing agent with $K_{2} C r_{2} O_{7}$ and turns it green.

Hence, both the statements are true.

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