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Measurement of Volume

A gaseous mix...

Question

A gaseous mixture of ethene, ethane and methane having total volume $150 m l$ is subjected to combustion in excess of oxygen. If percentage of methane in the original mixture is $20 %$ then calculate volume (in ml) of $C O_{2} (g)$ which will be obtained at same temperature and pressure.

A

150 m l

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B

30 m l

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C

240 m l

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D

270 m l

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Solution

The correct option is D $270 m l$
$C H_{4} = 20 % o f 150 m l = 30 m l$ and $C_{2} H_{4} + C_{2} H_{6} = 120 m l$
$C_{2} H_{4} = x, C_{2} H_{6} = 120 - x$
$C H_{4} + 2 O_{2} \to C O_{2} (g) + 2 H_{2} O$
30 30
$C_{2} H_{4} + 3 O_{2} \to 2 C O_{2} + 2 H_{2} O$
x 2x
$C_{2} H_{6} + \frac{7}{2} O_{2} \to 2 C O_{2} + 3 H_{2} O$
120 -x 240-2x

$V_{C O_{2}} = 30 + 2 x + 240 - 2 x = 270 m l$

Option D is correct.

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