MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Empirical & Molecular Formula

A gaseous mix...

Question

A gaseous mixture of $N_{2}$ and $O_{2}$ containing $60 %$ by mole $N_{2}$ is allowed to react with each other according to the following equation.
$N_{2} + O_{2} \to N O_{2}$
If $92$ g of $N O_{2}$ is formed, find the mole of $N_{2}$ present in the mixture.

Open in App

Solution

Suppose the number of moles present in mixture is $x$ .
$\frac{1}{2} N_{2} 0.6 x + O_{2} 0.4 x \to N O_{2} 0.4 x$
The molar mass of $N O_{2}$ is $46$ g/mol. $92$ g of $N O_{2}$ is obtained.
$0.4 x \times 46 = 92$
$x = \frac{2}{0.4}$
So, $0.6 x = \frac{2}{0.4} \times 0.6 = 3$ .
Hence, the mole of $N_{2}$ present in the mixture is $3$ .

Suggest Corrections

thumbs-up

0

Similar questions

Q. A gaseous mixture of

N_{2}

O_{2}

60 %

N_{2}

is allowed to react with each other according to the following equation:

N_{2} + O_{2} \to N O_{2}

92

N O_{2}

is formed, find the mole of

N_{2}

present in the mixture.

N_{2} O_{4}

dissociates into gaseous

{N O}_{2}

according to the reaction

N_{2} O_{4} (g) ⇌ 2 {N O}_{2} (g)

300 K

1 a t m

pressure, the degree of dissociation of

N_{2} O_{4}

0.2

. If one mole of

N_{2} O_{4}

gas is contained in a vessel, then the density of the equilibrium mixture is:

10.0

L of a gaseous mixture of

N O_{2}

N_{2}

at STP through an

N a O H

solution, a mixture of

N a N O_{2}

N a N O_{3}

6.32

K M n O_{4}

is required to oxidise above

N a N O_{2}

H_{2} S O_{4}

X

percentage by mass of

N_{2}

is present in gaseous mixture, (

N_{2}

does not react with

N a O H

) then value of

100 X

Q. A gaseous mixture was prepared by taking equal moles of

N_{2}

O_{2}

at room temperature. If the total pressure of the gaseous mixture was found to be 1 atm, then the partial pressure of nitrogen

(N_{2})

in the gaseous mixture is:

N H_{4} N O_{2}

N H_{4} N O_{3}

are heated, gaseous products obtained are:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Percentage Composition and Molecular Formula

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Empirical & Molecular Formula

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon