MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Volume of Gases and Number of Moles

A gaseous mix...

Question

A gaseous mixture of $O_{2}$ and $N_{2}$ in a closed vessel having mass 1g occupies $750 m L$ at NTP. Volume of $O_{2}$ in the mixture at $N T P$ is?

A

400 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

350 m L

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

450 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

300 m L

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $350 m L$
We know that
No. of moles $= \frac{v o l u m e o f s o l u t i o n}{v o l u m e o f s o l u t i o n a t N T P}$
No. of moles of $O_{2}$ + No. of moles of $N_{2}$
Let mass of $N_{2}$ is $x$
So, mass of $O_{2}$ is $1 - x$
Total moles $= \frac{1 - x}{32} + x 28$
So, on putting the values in formula, we have
$\frac{1 - x}{32} + x 28 = \frac{750 L}{22.4 L * 1000}$
On solving
$x = 0.5$
So, mass of $O_{2} = 1 - 0.5 = 0.5$ g
Volume of $O_{2}$ in solution
No. of moles $O_{2} = \frac{v o l u m e o f O_{2} i n s o l u t i o n}{22.4 L}$
$ \frac {0.5} {32} = \frac {V} {22.4 L}
$V = 350 m l$

Suggest Corrections

thumbs-up

0

Similar questions

600 m

of a mixture of

O_{3}

O_{2}

1 g

N T P

. Calculate the volume of ozone in the mixture.

600 ml of a mixture of O3 and O2 weighs 1g at NTP. Calculate the volume of ozone in the mixture

600 m L

of a mixture of

O_{3}

O_{2}

1 g

at NTP. Calculate the volume (mL) of ozone in the mixture.

Q. The density of a mixture of

N_{2}

O_{2}

1.3 g L^{- 1}

. Calculate partial pressure of

O_{2}

Q. The density of a mixture of

O_{2}

N_{2}

at NTP is 1.3 g litre

^{- 1}

. Calculate partial pressure of

O_{2}

.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Volume of Gases and Number of Moles

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Volume of Gases and Number of Moles

Standard X Chemistry

Join BYJU'S Learning Program

CrossIcon