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Question

A gaseous mixture was prepared by taking equal moles of N2 and O2 at room temperature. If the total pressure of the gaseous mixture was found to be 1 atm, then the partial pressure of nitrogen (N2) in the gaseous mixture is:

A
0.6 atm
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B
1 atm
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C
0.5 atm
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D
0.9 atm
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Solution

The correct option is C 0.5 atm
Given
nO2=nN2
P = Total pressure = 1 atm
PN2=nN2nO2+nN2×1=nN22nN2×1=12=0.5 atm

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