A gaseous reaction : $A_{2} (g) ⇌ B (g) + \frac{1}{2} C (g)$ shows increase in the pressure from 100 mm to 120 mm in 5 min. The rate of disappearance of $A_{2}$ is:

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Solution

$A_{2} (g) \to B (g) + \frac{1}{2} C (g)$

100 0 0 ---------------- initial
100-P P P/2 ---------------- after 5 min

After 5 minutes

Total pressure $\Rightarrow (100 - P) + P + \frac{P}{2} = 120 m m$

$\frac{P}{2} = 20$

$P = 40 m m$

So, rate of disappearance of $A_{2} = \frac{40 m m}{5 m i n}$
$= 8 m m / m i n u t e$

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