A gaseous system has a volume of $580 c m^{3}$ at a certain pressure. If its pressure is increased by $0.96 a t m$ , its volume becomes $100 c m^{3}$ . Determine the pressure of the system.

Open in App

Solution

Applying Boyle's law
$P \times 580 = (P + 0.96) 100$
$⟹ P = 0.2 a t m$

Suggest Corrections

Similar questions

Q. A gas has a volume of

580 c m^{3}

at a certain pressure.If its pressure is increased by 0.96 atm,its volume becomes

100 c m^{3}

.The new pressure of the gas is:

A given mass of ideal gas has volume (V) at pressure (P) and the room temperature. If its pressure is first increased by 50% and then decreased by 50% (both at constant temperature only), the volume becomes.

Q. Pressure-volume (PV) work done by an ideal gaseous system at constant volume is: (where

E

is internal energy of the system)

Q. The certain volume of a gas exerts on its walls some pressure at a particular temperature. It has been found that by reducing the volume of the gas to half of its original value the pressure becomes twice that of the initial value at a constant temperature. This happens because:

Q. If a gas kept at 1 bar pressure, has it volume decreased and made

\frac{1}{4}

of the initial volume, then its pressure becomes, if the temperature remains constant :

Join BYJU'S Learning Program

A gaseous system has a volume of 580 cm3 at a certain pressure. If its pressure is increased by 0.96 atm, its volume becomes 100 cm3. Determine the pressure of the system.

Applying Boyle's lawP×580=(P+0.96)100⟹P=0.2 atm

A gaseous system has a volume of $580 c m^{3}$ at a certain pressure. If its pressure is increased by $0.96 a t m$ , its volume becomes $100 c m^{3}$ . Determine the pressure of the system.

Applying Boyle's law
$P \times 580 = (P + 0.96) 100$
$⟹ P = 0.2 a t m$