wiz-icon
MyQuestionIcon
MyQuestionIcon
12
You visited us 12 times! Enjoying our articles? Unlock Full Access!
Question

A gasesous mixture contains three gases N2, O2 and CO2 with a total number of moles of 10 and total pressure of 10 atm. The partial pressure of N2 is 3 atm . The pressure is reduced to 9 atm if the gases is passed through alkaline pyrogallol. If CO2 has molecular weight of 44 g/mol. Then, the weight of CO2 (in grams) present in the mixture will be:

Open in App
Solution

Given total pressure (P)=10 atm
Given,
total number of moles; nN2+nO2+nCO2=10
The gas O2 is absorbed by pyrogallol. Hence the loss of pressure is due to O2.

10nO2nN2+nO2+nCO2×10=9 atm


Hence the number of moles of O2 is 1.
PN2=3 atm, PO2=1 atm, nN2=3, nO2=1
PN2=xN2×P(total)=nN2nN2+nO2+nCO2×10
=nN210×10nN2=3

nCO2=10(nN2+nO2)=104=6
Weight of C=6×44=264 g

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
VSEPR Theory and Dipole Moment
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon