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Charging of Capacitors

A Gaussian su...

Question

A Gaussian surface in the figure is shown by dotted line. The electric field on the surface will be:

A

due to

q_{1}

and

q_{2}

only

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B

due to

q_{2}

only

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C

zero

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D

due to all

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Solution

The correct option is D due to all
The electric field at any point is the resultant effect of all charges. So the electric field on surface will be due to all charges in this system.

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Similar questions

Q. Assertion :Four point charges

q_{1}, q_{2}, q_{3}

q_{4}

are shown in figure. The flux over the shown Gaussian surface depends only on charges

q_{1}

q_{2}

. Reason: Electric field at all points on Gaussian surface depends only on charges

q_{1}

q_{2}

.

Q. Four point charges

q_{1}, q_{2}, q_{3}

q_{4}

are as shown in figure. The flux over the shown Gaussian surface depends only on charges

q_{1}

q_{2}

.
Reason: Electric field at all points on Gaussian surface depends only on charges

q_{1}

q_{2}

.

(A)

: Four point charges

q_{1}, q_{2}, q_{3}

q_{4}

are as shown in figure. The flux over the shown gaussian surface depends only on charges

q_{1}

q_{2}

(R)

: Electric field at all points on gaussian surface is depends only on charges

q_{1}

q_{2}

Select the most appropriate answer from the options given below

Q. In the given question, a statement of Assertion

(A)

is given, followed by a corresponding statement of Reason

(R)

just below of it. Mark the correct answer.

Assertion

(A)

: Four point charges

q_{1}, q_{2}, q_{3} and q_{4}

are as shown in figure. The flux over the shown Gaussian surface depends only on charges

q_{1} and q_{2}

(R)

: Electric field at all points on Gaussian surface depends only on charges

q_{1} and q_{2}

Q. The diagram shows four charges

q_{1}, q_{2}, q_{3}

q_{4}

all lying in the plane of the page. The diagram also shows the dotted circle that represents the cross-section of a spherical Gaussian surface. Point

P

is a single point on that surface.
Which of the charges contributes to the electric field at point

P

?

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