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Question
A gene has two alleles P(dominant) and p(recessive). The homozygous recessive combination leads to death in, the embryo stage. If two individuals with genotype Pp are mated, out of the offspring that survive to adulthood, what is the probability of the genotype to be Pp?
A gene has two alleles P(dominant) and p(recessive). The homozygous recessive combination leads to death in, the embryo stage. If two individuals with genotype Pp are mated, out of the offspring that survive to adulthood, what is the probability of the genotype to be Pp?
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Solution
The correct option is B 0.75
A particular gene has two alleles, P (dominant) and p (recessive). It is given that when a fetus has homozygous recessive alleles (pp), the fetus will die in the embryo stage. When two individuals with genotype Pp are mated, they will produce two types of gametes with allele P and p. Usually, the offsprings are produced in the ratio of 1:2:1 (PP:Pp: pp). However, out of these, all the offsprings with genotype pp will die. Hence, there will 0.75 probability of the genotype of an offspring to be Pp and 0.25 probability of the genotype of an offspring to be PP.Thus, the correct answer is '0.75.'
A particular gene has two alleles, P (dominant) and p (recessive). It is given that when a fetus has homozygous recessive alleles (pp), the fetus will die in the embryo stage. When two individuals with genotype Pp are mated, they will produce two types of gametes with allele P and p. Usually, the offsprings are produced in the ratio of 1:2:1 (PP:Pp: pp). However, out of these, all the offsprings with genotype pp will die. Hence, there will 0.75 probability of the genotype of an offspring to be Pp and 0.25 probability of the genotype of an offspring to be PP.
Thus, the correct answer is '0.75.'
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