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Question

A gene locus has two alleles A and a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?

A
0.16 (AA); 0.36 (Aa); 0.48 (aa)
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B
0.36 (AA); 0.48 (Aa); 0.16 (aa)
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C
0.16 (AA); 0.24 (Aa); 0.36 (aa)
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D
0.16 (AA); 0.48 (Aa); 0.36 (aa)
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Solution

The correct option is D 0.16 (AA); 0.48 (Aa); 0.36 (aa)
Frequency of dominant allele (p) = 0.4
Applying Hardy Weinberg equilibrium:
p + q = 1
q = 1 - 0.4 = 0.6
p2+q2+2pq=1
Frequency of homozygous dominant genotype, p2 (AA) = 0.42= 0.16
Frequency of heterozygote, 2pq (Aa) = 2 × 0.4 × 0.6 = 0.48
Frequency of homozygous recessive genotype, q2 (aa) = 0.62 = 0.36

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