Question

A generator produces time varying voltage given by $E=240\sin 120t$, where $t$ is in second. The average value of voltage for the half cycle is -

• A. $123\text{V}$
• B. $133\text{V}$
• C. $143\text{V}$
• D. $153\text{V}$

Answer 1

The correct option is D $153\text{V}$

Given:

$E=240\sin 120t$

So, $E_0=240\text{V}$

We know that the average value of voltage of an AC source for a half cycle is given by,

$E_{avg}=\frac{2E_0}{\pi }$

$\Rightarrow E_{avg}=\frac{2\times 240}{\pi }=153\text{V}$