A geostationary satellite has an orbital period of

2 hours

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6 hours

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24 hours

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12 hours

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Solution

The correct option is C 24 hours
For the satellite to be 'synchronous/stationary' with the Earth, its period of revolution should be equal to Earth's rotation. So, the period of revolution is close to 24 hours.

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A geosynchronous satellite is a satellite that orbits the earth with an orbital period of 24 hours, thus matching the period of the earth's rotational motion. A special class of geosynchronous satellites is a geostationary satellite. A geostationary satellite orbits the earth in 24 hours along an orbital path that is parallel to an imaginary plane drawn through the Earth's equator. Such a satellite appears permanently fixed above the same location on the Earth. If a geostationary satellite wishes to orbit the earth in 24 hours (86400 s), then how high above the earth's surface must it be located? (Given: $M_{e a r t h} = 5.98 \times 10^{24} k g, R_{e a r t h} = 6.37 \times 10^{6} m$ )