Question

A geostationary satellite is moving in a circular orbit at a height $36000km$ from the surface of earth$.$ calculate its speed if it takes $24$ hours to revolve around the earth$?$

$($give radius of earth equal $6400km$ $)$

Answer 1

The radius of the orbit $=6400+36000=42400km$

circumference of the orbit $2\pi R$

$=2\times 3.14\times 42400$

$=266272km$

$speed=\frac{Dis\tan ce}{Time}$

$=\frac{266272}{24}=11094.67km/h.$