Question

A geostationary satellite is orbiting the earth at a height of $6$R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height of $2.5$R from the surface of the earth is _________ hours.

Answer 1

using kepler's law,

$\frac{T{1}^2}{T{2}^2}=\frac{R{1}^3}{R{2}^3}$

$T_1=24hrs$

$T_2=8.48hr$