A geostationary satellite is revolving around the earth. Now if the orbital speed is doubled, then

Total energy becomes zero.

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Satellite will leave circular orbit, but continues motion in an elliptical orbit.

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Satellite will leave orbit & the total energy becomes positive.

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Force between the earth & satellite becomes zero.

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Solution

The correct option is C Satellite will leave orbit & the total energy becomes positive.
In a circular orbit,
K.E = a
P.E = - 2a
T.E = - a

After velocity becomes double,
K.E = 4a
P.E = - 2a
T.E = 2a > 0

Therefore, the particle will leave orbit and total energy becomes positive.

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A geostationary satellite is revolving around the earth. Now if the orbital speed is doubled, then

The correct option is C Satellite will leave orbit & the total energy becomes positive.In a circular orbit, K.E = a P.E = - 2a T.E = - a After velocity becomes double, K.E = 4a P.E = - 2a T.E = 2a > 0 Therefore, the particle will leave orbit and total energy becomes positive.

The correct option is C Satellite will leave orbit & the total energy becomes positive.
In a circular orbit,
K.E = a
P.E = - 2a
T.E = - a

After velocity becomes double,
K.E = 4a
P.E = - 2a
T.E = 2a > 0

Therefore, the particle will leave orbit and total energy becomes positive.