A geyser has a label $2 k W, 240 V$ . What is the cost of using it for $30 m i n u t e$ , if the cost of electricity is $R s 3$ per commercial unit?

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Solution

Step 1: Given:
Geyser marked $2 k W, 240 V$ means
Power(P) = $2 k W$
Voltage(V) = $240 V$
Time= $30 m i n = \frac{30}{60} h o u r s = 0.5 h o u r s$
Cost per commercial unit = $R s 3$
Step 2: Finding electrical energy consumed.
$e n e r g y c o n s u m e d = p o w e r \times t i m e = 2 k W \times 0.5 h o u r s e n e r g y c o n s u m e d = 1 k W h$
which means $1$ commercial unit.
Step 3: Finding the cost of electricity
Therefore, the cost of electricity = $R s 3 \times 1 = R s 3$
Hence, the cost of electricity is $R s 3$ .

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