Given, the water is flowing at a rate of 3.0 litre/ min , temperature changes from 27 ∘ C to 77 ∘ C and the heat of combustion is 4.0× 10 4 J/g .
Let specific heat of water be c.
Let Q be the total heat used, then
Q=mcΔT
Here, m is the mass of water flowing, ΔT is the temperature change.
Substitute the values in the above expression.
Q=3000×4.2×( 77−27 ) =6.3× 10 5 J/ min
Let R be the rate of consumption of the fuel, then
R= Q heat of combustion
Substitute the value in the above expression,
R= 6.3× 10 5 4× 10 4 =16 g/ min
Hence, the rate of combustion of the fuel is 16 g/ min .