A giant refracting telescope has an objective lens of focal length 15 m. If an eyepiece of focal length 1.0 cm is used, what is the angular magnification of the telescope?

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Solution

Given,

Focal length of objective, $f_{o} = 15 m$

Focal length of eye-piece, $f_{e} = 1 c m$ $= 10^{- 2} m$

Angular magnification, $m = \frac{f_{o}}{f_{e}}$

$= \frac{15}{10^{- 2}}$

$= 1500$

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A giant refracting telescope has an objective lens of focal length 15 m. If an eyepiece of focal length 1.0 cm is used, what is the angular magnification of the telescope?

Given,Focal length of objective, fo=15mFocal length of eye-piece, fe=1cm =10−2m Angular magnification, m=fofe=1510−2=1500

Given,

Focal length of objective, $f_{o} = 15 m$

Focal length of eye-piece, $f_{e} = 1 c m$ $= 10^{- 2} m$

Angular magnification, $m = \frac{f_{o}}{f_{e}}$

$= \frac{15}{10^{- 2}}$

$= 1500$