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Question

A girl having mass of 35kg sits on a trolley of mass 5kg. The trolley is given an initial velocity of 4 ms1 by applying a force. The trolley comes to rest after traversing a distance of 16m. How much work is done by the girl on the trolley?

A
0 J
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B
320 J
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C
280 J
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D
100 J
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Solution

The correct option is C 280 J
Mass of girl =35kg
Mass of trolley = 5kg
Total Mass =35+5=40kg
u=4m/s,v=0m/s,s=16m
By 3rd equation of motion, v2=u2+2as
02=42+2a(16)
a=0.5 ms2
force exerted on trolley=40×0.5
=20N
Work done on trolley = 20×16J
=320J
Work done by the girl = F.s
=Mgirl×retardation×s
=35×0.5×16J
=280J

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