A girl is carrying a school bag $3 k g$ on her back and moves $200 m$ on a leveled road. The work done against the gravitational force will be $(g = 10 m s^{- 2})$

6 \times 10^{3} J

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6 J

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0.6 J

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0 J

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Solution

The correct option is D $0 J$
The height of the bag from the ground always remains constant throughout the journey.
$\Rightarrow$ $s = 0$
$\Rightarrow$ $W = F * s$
$\Rightarrow$ $W = 0 J$
hence the work done against the gravitational force will be zero.

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