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Question

A girl moves along the boundary of a square field of side 10 m in 40 s. What will be the magnitude of displacement of the girl at the end of 2 minutes 20 seconds?


  1. 10 m

  2. 3.14 m

  3. 20 m

  4. 102 m


Solution

The correct option is D

102 m


Distance covered in one round = 4 x 10 m = 40 m

Time taken = 40 s

Speed = 4040 = 1 m/s

So distance covered in 2 min 20 s = 1 m/s ×(2×60+20) s = 140 m

No. of rounds completed = 14040 = 3.5

If it starts from point A, it will be at C after 3.5 rounds.

Hence displacement = AC = (102+102) 102 m

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