a girl of mass 40 kg jumps with a horizontal velocity of 5 M per second on to a stationary cart with fractionless wheels . the mass of the cat is 3 kg what is her velocity as the car starts moving ?assume that there is no external unbalanced force working in the horizontal direction .

Open in App

Solution

no external force => momentum is constant.

momentum of girl = 40 * 5 = 200 kg-m/sec
momentum of girl and cart = total momentum of the girl + momentum of cart
= 200 + 0 = 200 kg m/sec
speed = 200 / (40 + 3)
= 4.65 m/sec

Suggest Corrections

Similar questions

Q. A girl of mass

40 k g

jumps with a horizontal velocity of

5 m s^{- 1}

onto a stationary cart with frictionless wheels. The mass of the cart is 3 kg. What is her velocity as the cart starts moving? Assume that there is no external unbalanced force working in the horizontal direction.

Q. A motor car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is reduced to 18 km/h in 4s by an unbalanced external force. The magnitude of force applied is

A car of mass 1200 kg is moving along a straight line with a uniform velocity of 90 $k m p h$ . Its velocity is slowed down to 18 $k m p h$ in 4 s by an unbalanced external force. Calculate the change in momentum and the magnitude of the force required. [3 MARKS]

Q. If 2 bodies a car & a truck are moving in same direction ( no external force is applied ) so how are they moving in same direction because no gravity should be there & if in space they can’t move in same direction they might be footing?

An object experiences a net zero external unbalanced force. Is it possible for the object to be traveling with a non-zero velocity? If yes, state the conditions that must be placed on the magnitude and direction of the velocity. If no, provide a reason.

Join BYJU'S Learning Program

a girl of mass 40 kg jumps with a horizontal velocity of 5 M per second on to a stationary cart with fractionless wheels . the mass of the cat is 3 kg what is her velocity as the car starts moving ?assume that there is no external unbalanced force working in the horizontal direction .

no external force => momentum is constant. momentum of girl = 40 * 5 = 200 kg-m/sec momentum of girl and cart = total momentum of the girl + momentum of cart = 200 + 0 = 200 kg m/sec speed = 200 / (40 + 3) = 4.65 m/sec

no external force => momentum is constant.

momentum of girl = 40 * 5 = 200 kg-m/sec
momentum of girl and cart = total momentum of the girl + momentum of cart
= 200 + 0 = 200 kg m/sec
speed = 200 / (40 + 3)
= 4.65 m/sec