A girl of mass $50 k g$ climbs a flight of $100$ stairs each measuring $0.25 m$ in height, in $20 s$ . Find the force acting on the girl. [Take g = $10 \frac{m}{s^{2}}$ ]

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Solution

Given:
Mass of girl= $50 k g$
No. of stairs= $100$
Height of one stair= $0.25 m$
Time = $20 s$
g= $10 \frac{m}{s^{2}}$

Analyzing problem:
Force acting on the girl = Weight of the girl

Formula used: $f = W = m g$

⇒ $f = 50 \times 10$
$= 500 N$
Hence, $500 N$ force is acting on the girl.

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