A girl of mass $50 k g$ climbs a flight of $100$ stairs each measuring $0.25 m$ in height in $20 s$ .[Take g= $10 \frac{m}{s^{2}}$ ]
Find gain in potential energy.

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Solution

Given:
Mass= $50 k g$
g= $10 \frac{m}{s^{2}}$
Height of one stair= $0.25 m$

To find the height of $100$ stairs :
Height of $100$ stairs= $100 \times 0.25 = 25 m$

Formula used:
The gain in potential energy $= m g \times h$

To apply the formula:
$E_{P} = 50 \times 10 \times 25 = 12500 J$

Hence, the gain in potential energy is $12500 J$ .

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A girl of mass 50kg climbs a flight of 100 stairs each measuring 0.25m in height in 20s.[Take g=10ms2]Find gain in potential energy.

Given:Mass=50kgg=10ms2Height of one stair=0.25m To find the height of 100 stairs :Height of 100stairs=100×0.25=25m Formula used: The gain in potential energy=mg×h To apply the formula:EP=50×10×25=12500J Hence, the gain in potential energy is 12500J.

A girl of mass $50 k g$ climbs a flight of $100$ stairs each measuring $0.25 m$ in height in $20 s$ .[Take g= $10 \frac{m}{s^{2}}$ ]
Find gain in potential energy.