A girl thows a water filled balloon on the eve of Holi with a velocity 12 ms-1 at an angle of 60- with the horizontal- It hits a car at the same height of throw approaching her at 15 ms-1- Find the initial distance of the car from her-

Time of flight of the balloonT=2u sinθg=2×12×√(3)210=2.07 s; Range of the balloon R=u sin 2θg=12×12×√(3)10×2=13 m Distance travelled by the car during this tim ...

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Standard XIII

Physics

The Symmetry of the Path Traced

A girl thows ...

Question

A girl thows a water filled balloon on the eve of Holi with a velocity 12 ms $^{- 1}$ at an angle of $60^{\circ}$ with the horizontal. It hits a car at the same height (of throw) approaching her at 15 ms $^{- 1}$ . Find the initial distance of the car from her.

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Solution

The correct option is C $44$ m
Time of flight of the balloon $T = \frac{2 u sin θ}{g} = \frac{2 \times 12 \times \frac{\sqrt{3}}{2}}{10} = 2.07 s$ ;
Range of the balloon
$R = \frac{u sin 2 θ}{g} = \frac{12 \times 12 \times \sqrt{3}}{10 \times 2} = 13 m$
Distance travelled by the car during this time $= 15 (2.07)$
Distance of car from her $= 13 + 15 (2.07) = 44 m$

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A girl thows a water filled balloon on the eve of Holi with a velocity 12 ms−1 at an angle of 60∘ with the horizontal. It hits a car at the same height (of throw) approaching her at 15 ms−1. Find the initial distance of the car from her.

The correct option is C 44 mTime of flight of the balloonT=2usinθg=2×12×√3210=2.07 s; Range of the balloon R=usin2θg=12×12×√310×2=13 m Distance travelled by the car during this time =15(2.07) Distance of car from her =13+15(2.07)=44 m

A girl thows a water filled balloon on the eve of Holi with a velocity 12 ms $^{- 1}$ at an angle of $60^{\circ}$ with the horizontal. It hits a car at the same height (of throw) approaching her at 15 ms $^{- 1}$ . Find the initial distance of the car from her.