Question

A girl thows a water filled balloon on the eve of Holi with a velocity 12 ms${}^{-1}$ at an angle of ${60}^{\circ }$ with the horizontal. It hits a car at the same height (of throw) approaching her at 15 ms${}^{-1}$. Find the initial distance of the car from her.

• A. $13$ m
• B. $31$ m
• C. $44$ m
• D. $18$ m

Answer 1

The correct option is C $44$ m

Time of flight of the balloon$T=\frac{2u\sin \theta }{g}=\frac{2\times 12\times \frac{\sqrt{3}}{2}}{10}=2.07s$;
Range of the balloon
$R=\frac{u\sin 2\theta }{g}=\frac{12\times 12\times \sqrt{3}}{10\times 2}=13m$
Distance travelled by the car during this time $=15\left(2.07\right)$
Distance of car from her $=13+15\left(2.07\right)=44m$