A girl throws a ball vertically upwards with an initial speed of 15m/s. The ball was released when it was at 2.0m above the ground. The girl catches it at the same point as the point of projection. What is the maximum height reached by the ball?
A
11.5m
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B
13.5m
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C
15.5m
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D
17.5m
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Solution
The correct option is B13.5m The ball will continue to move upwards as long as it has velocity. At maximum height v=0. We choose point of projection as origin, and upward direction to be positive.
From the equation, v2y=u2y+2ayy v2y=u2y−2gy
At maximum height, ymax=u2y2g =1522×9.8=11.5 y=ymax+2=11.5+2=13.5m