A girl weighing 400 N climbs a vertical ladder. If the value of g be 10 $m s^{- 2},$ the work done by her after climbing 2 m will be:

(a) 200 J

(b) 800 J

(c) 8000 J

(d) 2000 J

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Solution

F = 400 N

g = 10 $m s^{- 2}$

F = m $\times$ g

m = $\frac{F}{g}$ = $\frac{400}{10}$ = 40

W = F $\times$ d
W = mg $\times$ 2
= 40 $\times$ 10 $\times$ 2 = 800 J

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Similar questions

400 N

g

10 m s^{- 2}

2 m

g = 10 m s^{- 2}

A man of mass 50 kg climbs up a ladder of height 10 m. Calculate:

(i) the work done by the man, and

(ii) the increase in his potential energy. (g = 9.8 m $s^{- 2}$ ).

80 k g

20 / k g

40

25 c m

20 s e c o n d s

g = 10 m / s^{2}

50 k g

100 m

g = 9.8 m / s^{2}

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