A given circle $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ touches the x-axis and intersects the y-axis at 2 points. How many values of x are possible for y = 0.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
1

Its given that the circle touches x-axis and intersects y-axis at 2 points. Lets draw such a circle.

Its clear that when $y = 0$

There is only one point touching the x-axis.

$∴$ There is only one solution possible. At the same time when $x = 0$ ; the circle will have 2 solutions for 'y'.

Suggest Corrections

Similar questions

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

If $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ intersects the x-axis at (a,0) and (b,0) ,then $\frac{a + b}{2} = - g$ .

x^{2} + y^{2} + 2 g x + 2 f y + c = 0

The circle $x^{2} + y^{2} + 2 g x + 2 f y + c = 0$ does not intersect x-axis, if

Join BYJU'S Learning Program