a given mass of a gas occupies 143 cc at 17degree Celsiusand 70 mm of hg pressure what will be its volume at 27degree celsiusand 280 mm of Hg

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Solution

Dear student,

We can apply here the combined gas law: $\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$

We can solve the above expression for V₂,

$\frac{70 m m H g \times 143 c c}{290 K} = \frac{280 m m H g \times V_{2}}{300 K} V_{2} = \frac{70 m m H g \times 143 c c \times 300 K}{290 K \times 280 m m H g} = 37 c c$

Hence, Volume = 37 cc.

Best Wishes !

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a given mass of a gas occupies 143 cc at 17degree Celsiusand 70 mm of hg pressure what will be its volume at 27degree celsiusand 280 mm of Hg

Dear student, We can apply here the combined gas law:P1V1T1=P2V2T2 We can solve the above expression for V2, 70 mm Hg×143 cc290 K=280 mm Hg×V2300 KV2 = 70 mm Hg×143 cc×300 K290 K×280 mm Hg=37 cc Hence, Volume = 37 cc. Best Wishes !