A given mass of a gas occupies 240ml at 800mm of Hg. What volume will the gas occupy if the pressure is increased to 1200mm of Hg, temperature remaining constant?

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Solution

Dear Student,

The computation is expressed below based on Ideal gas law,

$\frac{P_{1} V_{1}}{P_{2} V 2} = \frac{n R T_{1}}{n R T_{2}} P_{1} V_{1} = P_{2} V_{2} 800 \times 240 = 1200 \times V_{2} V_{2} = 160 m l$

Regards.

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A given mass of a gas occupies 240ml at 800mm of Hg. What volume will the gas occupy if the pressure is increased to 1200mm of Hg, temperature remaining constant?

Dear Student, The computation is expressed below based on Ideal gas law, P1V1P2V2=nRT1nRT2P1V1 = P2V2800×240=1200×V2V2=160 ml Regards.

Dear Student,

The computation is expressed below based on Ideal gas law,

$\frac{P_{1} V_{1}}{P_{2} V 2} = \frac{n R T_{1}}{n R T_{2}} P_{1} V_{1} = P_{2} V_{2} 800 \times 240 = 1200 \times V_{2} V_{2} = 160 m l$

Regards.