A given mass of gas expands from the state A to the state B by three paths 1, 2 and 3 as shown in the figure. If W1,W2 and W3 respectively be the work done by the gas along three paths then:
A
W1>W2>W3
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B
W1<W2<W3
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C
W1=W2=W3
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D
W1<W2;W1<W3
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Solution
The correct option is CW1<W2<W3 Work done can be calculated by calculating the area under P−V diagram.
Let A1, A2 and A3 be the area under the P−V graph for 1, 2 and 3 process respectively.