A given mass of ideal gas has volume (V) at pressure (P) and the room temperature. If its pressure is first increased by 50% and then decreased by 50% (both at constant temperature only), the volume becomes.
A
4V/3
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B
3V/4
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C
V
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D
4V/5
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Solution
The correct option is A 4V/3 P1V1=P2V2Firstincreasedby50i.eP2=1.5P1V2=11.5V1Nowdecreasedby50i.eP3=P22=1.52P1P2V2=P3V3V3=2V2V3=21.5V1V3=2015V1=43V1