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Question

A given piece of wire of length L radius r and resistance R is stretched uniformly to a wire of radius r2. The new resistance is:


A

16 R

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B

4 R

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C

R4

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D

R16

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Solution

The correct option is A

16 R


As R = ρLA and volume = L x A = Constant.

Area becomes 14th of the initial value and length becomes 4 times the initial value.

So, resistance increases by 16 times.


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