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Ammonia

A given sampl...

Question

A given sample of a pure compound contains $9.81$ g of zinc, $1.8 \times 10^{23}$ atoms of chromium and $0.6$ mole atoms of oxygen. What is the empirical formula of the compound ?

[Atomic mass : $Z n = 65.4, C r = 52, O = 16$ ]

Z n {C r}_{2} O_{7}

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Z n {C r}_{2} O_{4}

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Z n C r O_{4}

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Z n {C r}_{2} O_{6}

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Solution

The correct option is A $Z n {C r}_{2} O_{4}$
Number of moles of $Z n = \frac{9.81}{65.4} = 0.15 m o l$
Number of moles of $C r = \frac{1.8 \times 10^{23}}{N_{A}} = 0.3 m o l$
Number of moles of $O = 0.6 m o l$
The molar ratio is $Z n : C r : O = 1 : 2 : 4$
So, the empirical formula of compound is $Z n {C r}_{2} O_{4}$ .

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