Question

A given volume of air at ${37}^{\circ }\text{C}$ exerts a pressure of $870\text{mm}$ of mercury. The temperature at which the pressure becomes $1740\text{mm}$ of $Hg$ is

• A. $200\text{K}$
• B. $305\text{K}$
• C. $620\text{K}$
• D. $310\text{K}$

Answer 1

The correct option is C $620\text{K}$

According to Gay-Lussac's law,
For constant volume,
$\frac{P}{T}=k$ (constant)
$\Rightarrow \frac{P_1}{T_1}=\frac{P_2}{T_2}$
$\Rightarrow \frac{870\text{mm}}{({37}^{\circ }+273)}=\frac{1740\text{mm}}{T_2}$
$\Rightarrow T_2=\frac{1740\times 310}{870}$
$\Rightarrow T_2=620\text{K}$