A glass bulb contains air at one atmosphere and $27^{o} C$ . The maximum pressure which the bulb can withstand is $2$ atmosphere. Find the temperature at which it bursts.

327 K

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127^{o} C

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327^{o} C

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227^{o} C

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Solution

The correct option is C $327^{o} C$
$\frac{P_{2}}{T_{2}} = \frac{P_{1}}{T_{1}} ⟹ T_{2} = \frac{2 a t m \times 300 K}{1 a t m} = 600 K = 327 ℃$

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A glass bulb contains air at one atmosphere and 27oC. The maximum pressure which the bulb can withstand is 2 atmosphere. Find the temperature at which it bursts.

The correct option is C 327oCP2T2=P1T1⟹T2=2atm×300K1atm=600K=327℃

A glass bulb contains air at one atmosphere and $27^{o} C$ . The maximum pressure which the bulb can withstand is $2$ atmosphere. Find the temperature at which it bursts.

The correct option is C $327^{o} C$
$\frac{P_{2}}{T_{2}} = \frac{P_{1}}{T_{1}} ⟹ T_{2} = \frac{2 a t m \times 300 K}{1 a t m} = 600 K = 327 ℃$