Question

A glass bulb contains air at one-atmosphere pressure and ${27}^{o}C$. The maximum pressure which the bulb can withstand is $2$ atmosphere. Find the temperature at which it bursts (in $K$).

Answer 1

According to Gay Lussac's law, the pressure of a given amount of gas held at constant volume is directly proportional to the Kelvin temperature, i.e.,

$P\propto T$

$\therefore \frac{P_1}{P_2}=\frac{T_1}{T_2}$

Let $T$ be the temperature at which the bulb burst.

Here,

$P_1=1atm$

$P_2=2atm$

$T_1=27℃=(27+273)K=300K$

$T_2=?$

$\therefore \frac{1}{2}=300T$

$\Rightarrow T=300\times 2=600K$

Hence the temperature at which the bulb bursts is $600K$.