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Question

A glass convex lens has a focal length of 20 cm in air. What will be its focal length, when it is completely immersed in a liquid of refractive index 1.63 ? ( Given aμg=1.5)

A
f1=127.4cm
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B
f1=125.4cm
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C
f1=120.4cm
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D
f1=18.75cm
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Solution

The correct option is D f1=18.75cm
fair =20 mμg=1.5μL=1.63 Using Lens formula 1fair =(μg1)(1R11R2)
120=(0.5)(1R11R2)(i) No lens immersed in liquid 1fliq=[aμ1aμg1][1R11R2]
1fliq=(1.631.51)(1R11R2)(ii)
Dividing i/(ii)
fliq20=0.5(1.631.55)×1.5fliq=0.5×1.5×200.8=18.75 cm

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